Index exceeds the number of array elements (1).

Question

Sam Frank 2020-6-14

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/548112-index-exceeds-the-number-of-array-elements-1

评论： Sam Frank 2020-6-18

t1=-1:0.1:0.5;
t2=0.6:0.1:3;
t= [t1 t2];
x1=0.6.*ones(size(t1));
x2=0.3.*ones(size(t2));
x=[x1 x2];
h=(exp(-t)).*(t>=0);
C=length(x)+length(h)-1;
X=0;
H=0;
for i=1: C
c(i) = 0;
for j=1:i
if(i-j+1>0)
c(i)= c(i)+ X(j).* H(i-j+1);
else
end
end
end
plot(c)

I'm trying to v=convolve x and h but everytime i run this it gives me the array size error.

I'm using MATLAB Online R2020a, and when I gave this code to someone who had RMATLAB2015a installed on their computer, there was no error.

error is in line 16:

c(i)= c(i)+ X(j).* H(i-j+1);

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KSSV 2020-6-14

What is that code? It is full of mess. What exactly you are trying?

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Answer 1

Ayush Goyal 2020-6-18

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/548112-index-exceeds-the-number-of-array-elements-1#answer_453036

编辑：Ayush Goyal 2020-6-18

在 MATLAB Online 中打开

From my understanding of the question you are trying to find the convolution of x and h but you are facing array size error. Error is due to different length of vectors x and h and you should transform the vectors x and h in new vectors X and H with the same length. Change the code for X and H and instead of iterating j from 1 to i iterate it from 1 to length(x)

t1=-1:0.1:0.5;
t2=0.6:0.1:3;
t= [t1 t2];
x1=0.6.*ones(size(t1));
x2=0.3.*ones(size(t2));
x=[x1 x2];
h=(exp(-t)).*(t>=0);
C=length(x)+length(h)-1;
X=[x,zeros(1,length(h))]; %zeropadding to have vectors of equal length
H=[h,zeros(1,length(x))]; %zeropadding to have vectors of equal length
for i=1: C
c(i) = 0;
for j=1:length(x) %Iterate it from 1 to length(x)
if(i-j+1>0)
c(i)= c(i)+ X(j).* H(i-j+1);
else
end
end
end
plot(c)