double integral with one variable

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Hi, I have been struggling to understand below double integral phenomenon. I am trying to solve an loop problem and in one small part of loop I need to take an definite double integral. If the formula contains two variables, I can get the correct answer. But, if the formula has just one variable (as shown below) I get the below error. How can I handle this problem?
Here is my simplified code;
syms x y;
A2=y^3;
f= matlabFunction(A2);
integrand = @(x,y)f(x,y);
Q2 = quad2d(integrand,-1,1,-1,1);
And the error I get from Matlab is below:
??? Error using ==> sym.matlabFunction>@(y)y.^3
Too many input arguments.
Error in ==> @(x,y)f(x,y)
Error in ==> quad2d>tensor at 355
Z = FUN(X,Y); NFE = NFE + 1;
Error in ==> quad2d at 169
[Qsub,esub] = tensor(thetaL,thetaR,phiB,phiT);
Error in ==> example at 7
Q2 = quad2d(integrand,-1,1,-1,1);
I would appreciate any help, idea, thought...

采纳的回答

Walter Roberson
Walter Roberson 2012-11-26
matlabFunction() by default creates a function handle that expects only as many input parameters as there are free variables in the symbolic function. You should specifically tell matlabFunction() which variables you wish to have in the calling sequence and in which order.

更多回答(1 个)

Ozan
Ozan 2012-11-28
Thank you for your answer Mr.Roberson. How can I handle my code? I mean, which changes I need to do to solve this issue?

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