Function returning matrix instead of vector

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Travis Craddock
Travis Craddock 2020-6-17
回答： Rafael Hernandez-Walls 2020-6-17
Hello,
I have made a function for use in least squares curve fitting of the form:
f=@(xf,xdata)xf(1)*(xf(4)+((xf(2)-xdata)/(xf(3)/2))).^2/(1+((xf(2)-xdata)/(xf(3)/2)).^2)
xf should have 4 parameters
When I test the function with
f(x0f,xdata)
with x0f = [1.0000, 462.7580, 1.8007, 0], and xdata a 15x1 column vector I get a 15x15 matrix as output, when I expect a 15x1 column vector. I believe the issue is that the f function has xdata squared (.^2) both in the numerator and denominator, but I don't know how to circumvent this as there is no way to isolate xdata. Any help is appreciated.
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Travis Craddock
Travis Craddock 2020-6-17
P.S. Entering this function into lsqcurvefit results in an error "Function value and YDATA sizes are not equal."

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采纳的回答

KSSV
KSSV 2020-6-17
编辑：KSSV 2020-6-17
Read about element by element operations.
Repalce * with .*, / with ./
f=@(xf,xdata)xf(1)*(xf(4)+((xf(2)-xdata)./(xf(3)/2))).^2./(1+((xf(2)-xdata)./(xf(3)/2)).^2) ;

更多回答（1 个）

Rafael Hernandez-Walls
f=@(xf,xdata)xf(1)*(xf(4)+((xf(2)-xdata)/(xf(3)/2))).^2./(1+((xf(2)-xdata)/(xf(3)/2)).^2)

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