How to pop the content of a matrix in a way like pop the content of a cell

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raym
raym 2020-6-19
评论： raym 2020-6-19
We know that the arguments of a function can be placed in a cell and call it like this:
aCell = {arg1,arg2,arg3};
myFunction(aCell{:});
Is there a way to do this for a vector instead?
I tried this way, but it does not work
aVector = [2 3 4 5];
myFun(aVector(:)) % this does not work, the argument is a column vector [2;3;4;5] instead.
Similarly,
aVec = [1 2 3];
aCell = {'d','dew',aVec(:)} % I would expect aCell is {'d','dew',1,2,3}, but it is {'d','dew',[1;2;3]},
Thanks.

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-6-19
Madhan's answer already shows how to use num2cell. Following just show how can you avoid the creation of a temporary variable
v = [1 2 3];
myFun(struct('a', num2cell(v)).a)
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Ameer Hamza
Ameer Hamza 2020-6-19
Timing will be higher because of the additional overhead of struct creation (num2cell() being equivalent in both cases). However, it is only a concern if the function myFun() is itself has very small execution time (in order of microseconds) or the number of input arguments is in millions. If timing is a primary considerations, then it will be faster to just take input as an array rather than splitting it into an argument list. The point about obfuscation seems valid.

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更多回答（2 个）

madhan ravi
madhan ravi 2020-6-19
编辑：madhan ravi 2020-6-19
aVector = [2 3 4 5];
aVector = num2cell(aVector);
myFun(aVector{:}) % ;)
Walter Roberson
Walter Roberson 2020-6-19
No there is not.
You can num2cell the vector and assign that to a variable and do expansion on that.
There are ways to use auxiliary anonymous functions to do the num2cell for you, and even to do cell expansion on the result, but when you proceed that way, the MATLAB parser will not know that multiple outputs are required and will pull out only the first value.

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