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Please help me with this as soon as possible

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carson yeoh
carson yeoh 2020-6-25
编辑： Walter Roberson 2020-6-25
Why do I get the same answer as 733 for all columns. The code I want is divide every single a with b so I use a./b but I end up getting all same 733. Why??? Please help .
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carson yeoh
carson yeoh 2020-6-25
I tried to calculate separetly and I got different answer for each column
but then I tried every way to combine it, i will get wab
Walter Roberson
Walter Roberson 2020-6-25
x = (r*sin(theta))/L;
Ok.
phi = asin(x);
asin() of a constant times sin(theta)... perhaps there is a trig identity that could be used, but it is not one of the common ones.
b = L*sin(phi);
phi is asin(x) and x = (r*sin(theta))/L so provided that r/L*sin(theta) happens to fail within the first period then sin(asin(x)) would be x, so for at least part of the theta range, L*sin(phi) -> L*sin(asin(x)) -> L*x -> L * r*sin(theta) / L -> r * sin(theta)
a = wab*r*sin(theta);
Look, there is an r*sin(theta) in there...
wbc = a./b
So wab*r*sin(theta) / (r * sin(theta)) -> wab
r/L is about 0.3 and 0.3*sin(theta) is going to be within the primary range for real-valued theta that is in the primary range.

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回答（1 个）

Rasul Khan
Rasul Khan 2020-6-25
编辑：Walter Roberson 2020-6-25
wab =733;r=0.0405;L=0.13;
theta = 0:0.1:2*pi;
x = (r*sin(theta))/L;
phi = asin(x);
a = wab*r*sin(theta);
b = L*sin(phi);
wbc = a./b
If you look at your code and replace the value of phi you will get
b = L * x
And calculating a./b wil give you 'wab' like @KSSV mentioned here
https://www.mathworks.com/matlabcentral/answers/554386-please-help-me-with-this-as-soon-as-possible#comment_912661

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