Second Element is not 1 but It is coming as 1
1 次查看(过去 30 天)
显示 更早的评论
Hello,
I have this matrix:
I saved this matrix in a list like : projectors_of_sigma_x_minus_sigma_z = [[(sqrt(2)-1);1],[(-sqrt(2)-1);1]];
and this is my code :
function B = CHSHmeasurement
B=zeros(2,2,2,2);
projectors_of_sigma_x_minus_sigma_z = [[(sqrt(2)-1);1],[(-sqrt(2)-1);1]];
B(:,:,2,1) = projectors_of_sigma_x_minus_sigma_z(1);
B(:,:,2,2) = projectors_of_sigma_x_minus_sigma_z(2);
end
But I have this result:
However I have not 1 as the second element of projectors_of_sigma_x_minus_sigma_z. I have [(-sqrt(2)-1);1] for the second element of projectors_of_sigma_x_minus_sigma_z(2); Where am I wrong ?
0 个评论
采纳的回答
madhan ravi
2020-6-25
编辑:madhan ravi
2020-6-25
>> B=zeros(2,2,2,2);
projectors_of_sigma_x_minus_sigma_z = [[(sqrt(2)-1);1],[(-sqrt(2)-1);1]]
B(:,:,2,1) = projectors_of_sigma_x_minus_sigma_z(1)
B(:,:,2,2) = projectors_of_sigma_x_minus_sigma_z(2)
projectors_of_sigma_x_minus_sigma_z =
0.4142 -2.4142
1.0000 1.0000
B(:,:,1,1) =
0 0
0 0
B(:,:,2,1) =
0.4142 0.4142
0.4142 0.4142
B(:,:,1,2) =
0 0
0 0
B(:,:,2,2) =
0 0
0 0
B(:,:,1,1) =
0 0
0 0
B(:,:,2,1) =
0.4142 0.4142
0.4142 0.4142
B(:,:,1,2) =
0 0
0 0
B(:,:,2,2) =
1 1
1 1
>>
You're copying a scalar to that entire page.
9 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!