How to accurately process an Anderson Darling test?

5 次查看（过去 30 天）

Isaac Valdez 2020-6-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/557446-how-to-accurately-process-an-anderson-darling-test

评论： Isaac Valdez 2020-7-1

I am conducting a Anderson Darling (Adtest) on a set of data and I am trying to verify if what I am getting is correct. However I am getting conflicting answers. In MATLAB I am getting the following:

Build_Array_Final{1}=[214.42,214.99,215.35,215.98,221.08,222.54,214.78,215,215.32,215.75,217.06,215.91,212.30,213.78,217.16,218.39,224.23,221.94...
    ,215.67,214.04,214.98,215.13]';
[h,p,adstat,cv] = adtest(Build_Array_Final{1},'Distribution','weibull');
% h =
%   logical
%    1
% p =
%    5.0000e-04
% adstat =
%     2.1490
% cv =
%     0.7374

This is what I get as my answer however I doubled check my values with "Minitab19" I am recieiving the following data:

If someone could help me identify where I am going wrong I would be greatful.

I am using ver 2020a

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Jeff Miller 2020-7-1

2
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/557446-how-to-accurately-process-an-anderson-darling-test#answer_459292

Looks to me like the same problem as in your previous question. MATLAB's 2-parameter Weibull starts from a minimum of 0, but Minitab seems to add a third parameter (Thresh) for the minimum, which it estimates at 212.1. If you subtract that number from all your observations and run your adtest command on the differences, I think MATLAB will give you the same results as Minitab.