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handle character minus character

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Ancalagon8
Ancalagon8 2020-7-10
Locked: Rena Berman 2025-1-13
I have two characters which contain '18:29:42.835' and '18:29:49.425'. How is it possible to subtrack t2-t1 so as to find duration?

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采纳的回答

madhan ravi
madhan ravi 2020-7-10
f = @(x) str2double(regexp(x,':','split'));
t1 = num2cell(f(t1)); % where t1 & 2 are your char arrays
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:})
  1 个评论
madhan ravi
madhan ravi 2020-7-10
f = @(x) str2double(regexp(x,'\D','split'));
t1 = num2cell(f(t1));
t2 = num2cell(f(t2));
Wanted = duration(t2{:})-duration(t1{:});
Wanted.Format = 'hh:mm:ss.SSSS'

更多回答（1 个）

Walter Roberson
Walter Roberson 2020-7-10
If you have a recent enough MATLAB version, pass the character vectors to duration() and then subtract one from the other.
If your MATLAB is a bit older, then you will need to split the vectors at the colons, then str2double() to get the individual components, and pass those to duration.
Or you could use sscanf() with a format of '%f:%f:%f' to get the numeric components and pass those to duration()

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