How to vectorize a find

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Matlab2010
Matlab2010 2012-12-11
x = zeros(1000,1);
x(76) = 1;
x(100) = 1;
x(200) = 1;
I can do:
first = find(x ==1, 1, 'first'); %the answer =76
but this is slow. I would like to speed this up. How? thanks
  1 个评论
Matlab2010
Matlab2010 2013-1-15
编辑：Matlab2010 2013-1-15
just going to put up some code which might help others looking for v fast finds in future:
Method 3 is incredibly fast (credit to Matt J!)
%METHOD 1
lastTimeValue_SLOW = arrayfun(@(x,y) find(data(x:end,2) <= y, 1, 'last'), trades, tradeTimePlusDt); %works but v slow!
%METHOD 2
lastTimeValue = NaN(length(trades),1);
for z = 1 : length(trades)
p=data(trades(z):end,2);
for kk = 1:length(p)
if(tradeTimePlusDt(z) <= p(kk))
lastTimeValue(z) = kk-1;
break;
end
end
end
%METHOD 3
%http://www.mathworks.co.uk/matlabcentral/newsreader/view_thread/304895
lastTimeValue_TEST = NaN(length(trades),1);
for z = 1 : length(trades)
I = histc(data(trades(z):end,2),[-inf;tradeTimePlusDt] );
temp = cumsum(I(1:z));
lastTimeValue_TEST(z) = temp(end);
end

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采纳的回答

Matt Fig
Matt Fig 2012-12-11
编辑：Matt Fig 2012-12-11
The last statement you show is vectorized, so the question is ill-posed. I think what you are asking for is a way to speed up the process.
Also, just how fast do you think it should be??
x = zeros(1000,1);
x(76) = 1;
x(100) = 1;
x(200) = 1;
tic,first = find(x ==1, 1, 'first');toc
Elapsed time is 0.000023 seconds. % That is slow???
.
.
.
EDIT
I did find a way to do it faster, but it will only work if you have a binary matrix as in your example. You can avoid the comparison as it is not necessary.
tic,first = find(x);first = first(1);toc
Elapsed time is 0.000012 seconds.
  3 个评论
显示 1更早的评论
Matt Fig
Matt Fig 2012-12-11
编辑：Matt Fig 2012-12-11
There is no find.m in MATLAB.
which find
built-in (C:\Program Files\MATLAB\R2011b\toolbox\matlab\elmat\@logical\find) % logical method
Matt Fig
Matt Fig 2012-12-11
Also, see my edit above for a faster method if you have a binary array.

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更多回答（2 个）

Sean de Wolski
Sean de Wolski 2012-12-11
If you only have zeros and ones and you are positive there is atleast one one, then you can use the second output from max().
[~,first] = max(x);
I don't know if this will be faster or not.
Mark Whirdy
Mark Whirdy 2012-12-11
编辑：Mark Whirdy 2012-12-11
a temporary vector of row numbers, then use your vector-of-interest & a logicsl statement to index this row-number vector
a =[1:size(x,1)]'; % row numbers
b=a(x==1); % logical indexing the populated rows
b(1) % first instance

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