draw a simple complex function

Question

0 个投票

assume z0 = x0 + y0 * i;

if abs(z-z0)=R

then abs(z-z0)-R describes a circle with center of z0 and radius of R;

how can we use matlab to draw it?

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

Answer 1

madhan ravi 2020-7-13

0 个投票

By defining z as a function of x and y and using fplot()

doc fplot

Answer 2

Alan Stevens 2020-7-13

0 个投票

How about:

 x0 = 1; y0 = 2;
 z0 = x0 + y0*i;
 R = abs(z0);
 theta = 0:1/360:2*pi;
 x = x0 + R*cos(theta); y = y0 + R*sin(theta);
 plot(x,y)

madhan ravi 2020-7-13

What about z?

Alan Stevens 2020-7-13

编辑：Alan Stevens 2020-7-13

Yes, z needs to be defined as well. I simply took it as zero here for simplicity (the main idea being the use of cos and sin theta).

Didn't think of fplot - a much better idea!