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How to search a number in a random string?

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Josy M
Josy M 2020-7-14
评论： Leon 2024-4-12
Hello :)
This time just a short question: I have random strings with characters and numbers. I (need) want to extract the number at the end of the string. The string consists evertime with some characters at the beginng and at the end a number. How does it work to get the number?
((( For me its difficult because i dont know how many characters are the beginning and i dont know how long the number is)))))
I saw this command. But i dont know to use it exactly.
text="tq3" %->3
text="v023"%->23
%or
text="ABCDEFRANDOM1234" %->1234
str=regexp(text,'(??????', 'match') %

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回答（2 个）

madhan ravi
madhan ravi 2020-7-14
编辑：madhan ravi 2020-7-14
str = str2double(regexp(text,'\d+$','match'))
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madhan ravi
madhan ravi 2020-7-14
Thanks Stephen ;). Sometimes MATLAB mobile gives wierd answer if the internet connection is not good.
Leon
Leon 2024-4-12
How would you adjust this to allow miscellaneous text after the number too, e.g. "thv123_gdf" => 123? Thanks.

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Rohit Anand
Rohit Anand 2020-7-14
编辑：Rohit Anand 2020-7-14
You can do it all in a few steps for better understanding.
  1. Use regexp to get the index from where we need to slice the string. (In the below example you will get index of '1').
  2. Slice the string from idx onwards to get the number at the end of the string.
  3. Convert the obtained numeric string into a double, using str2double
text="ABCDEF78RAN9DOM1234";
idx = regexp(text, '\d+$'); % Find the first index of the number
y = extractAfter(text, idx-1); % Slice the string
number = str2double(y) % convert to double
  2 个评论
madhan ravi
madhan ravi 2020-7-14
How does it differ from the answer I gave?
Stephen23
Stephen23 2020-7-14
"How does it differ from the answer I gave?"
More complex for no obvious benefit.

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