How to solve the following error : "Maximum number of function evaluations exceeded; increase OPTIONS.MaxFunEvals".

8 次查看(过去 30 天)
I need to maximize the objective function y = exp(x) using 'fmincon' and a -ve sign in the objective function.I have used upper & lower bounds of x as 300 and 400. When I run with y=exp(x), I get the error: Maximum number of function evaluations exceeded;
increase OPTIONS.MaxFunEvals.
When I run for y = exp(-x), I get the error:
Optimization terminated: first-order optimality measure less than options.TolFun and maximum constraint violation is less
than options.TolCon.
Active inequalities (to within options.TolCon = 1e-006):
lower upper ineqlin ineqnonlin
1
The code is :
function xout = s1
%---------------------------optimization-------------------
x0 = [300]; % Just some Initial Condition
ub = [400]; % Upper bounds
lb = [300]; % Lower bounds
F = @(x) obj(x);
xout = fmincon(F,x0,[],[],[],[],lb,ub); %optimization operator
function obj = obj(x)
y = exp(x)
obj = -y
end
end
Please help me as to how I can remove this error. Thanks.

采纳的回答

Walter Roberson
Walter Roberson 2012-12-17
options = struct('MaxFunEvals', 2000);
xout = fmincon(F, x0, [], [], [], [], lb, ub, options);
  4 个评论
Nitin Samuel
Nitin Samuel 2012-12-17
Thanks Mr.Roberson. I tried and it shows following error:
Maximum number of iterations exceeded; increase OPTIONS.MaxIter.
I have added "options = struct('MaxIter',2000);"
Still it shows the same...

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Get Started with Optimization Toolbox 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by