Help me generating this series of number.
显示 更早的评论
White flag.
I'm trying to make a series of number like below:
1
2
5
10
20
50
100
200
500
...
...
...
1000000000
2000000000
5000000000
but i need a for-end command first
for i=1:20
because i want to use that "20" in other procedure. And the generated numbers willl also be input in another procedure which requires them to be real positive integer.
could you help me?
采纳的回答
Andrei Bobrov
2011-4-17
without loop for
reshape(cumprod([1 2 5;10*ones(9,3)])',[],1);
with loop for
P = zeros(30,1);
for ii = 1:20
if rem(ii,2) == 0,
P(3*(ii/2)-2+(0:2)) = [1;2;5]*10^(ii/2-1);
end
end
3 个评论
Oleg Komarov
2011-4-17
Slightly faster alternatives:
reshape(bsxfun(@times,[1; 2; 5], 10.^(0:9)),[],1);
reshape([1; 2; 5] * 10.^(0:9),[],1);
Albaihaqi Albaihaqi
2011-4-18
Andrei Bobrov
2011-4-18
Because, it is necessary to fulfill your two conditions: length (P) = 30, i = 1:20
更多回答（1 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
2011-4-17
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
