Concatenate cells: making column and row headers

2012 12 17
3 个回答
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0 个投票

Hi,
I have a column and a row like this:
col={'cat1'; 'cat2'; 'cat3'}
row={'mouse1' 'mouse2' 'mouse3'}
I would like to make these as column and row headers (eventually for a table) like this such that my table looks like this:
I've attempted to use cat such that:
table=cat(2,col,row)
but it results in an error the dimensions are not consistent..
Thank you so much for your help and please let me know if I am not clear.

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Pedro Villena
Pedro Villena 2012-12-17

0 个投票

table(2:numel(row)+1) = row;
table(2:numel(col)+1,1) = col;

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Mich
Mich 2012-12-17
编辑：Mich 2012-12-17
That's it! The way that gave me the exact result was:
table(1:numel(row))=row;
table(1:numel(col),1)=col;
Thank you so much!! And to all the helpers, you are awesome!

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更多回答（2 个）

Honglei Chen
Honglei Chen 2012-12-17

0 个投票

table(2:4) = row;
table(2:4,1) = col;

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Mich
Mich 2012-12-17
Unfortunately i get a dimension mismatch error as well. I tried the method under Azzi's comment because with my real dataset I would not know the if it actually ended on the 4th row. Perhaps I am looking for something more like:
table={}
table(2:size(row,2))=row;
table(2:size(col,1),1)=col;
But I get a dimension mismatch.. Thank you for your response!!
Honglei Chen
Honglei Chen 2012-12-17
The code below works fine for me. If you get an error, you may need to make sure that your variable, table, is not defined previously with other dimensions. If that still didn't work out, please post your example with the error message.
>> col = {'a','b','c'}
col =
'a' 'b' 'c'
>> row = {'d','e','f'}
row =
'd' 'e' 'f'
>> table(2:numel(row)+1) = row
table =
[] 'd' 'e' 'f'
>> table(2:numel(col)+1,1) = col
table =
[] 'd' 'e' 'f'
'a' [] [] []
'b' [] [] []
'c' [] [] []

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Matt Fig
Matt Fig 2012-12-17
编辑：Matt Fig 2012-12-17

0 个投票

row={'cat1'; 'cat2'; 'cat3'};
col={'mouse1' 'mouse2' 'mouse3'};
figure
t = uitable('Data',[],...
'ColumnName',col,...
'RowName',row,...
'Position',[20 20 360 100])

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