passing 'varagin' and getting inputname() to work properly

Question

Adam 2012-12-21

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/57181-passing-varagin-and-getting-inputname-to-work-properly

Is it possible to pass 'varargin' to an internal function and still get inputname() to return the original variable names?

e.g.

function struct = temp( varargin )
    struct = parseInputs( varargin{1:end} )
end
function struct = parseInputs( varargin )
    struct.name1 = inputname(1);
    struct.name2 = inputname(2);
    struct.name3 = inputname(3);
    struct.name4 = inputname(4);
end

>> output = temp( a, b, c, d )

output =

    name1: 'a'
    name2: 'b'
    name3: 'c'
    name4: 'd'

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Answer 1

Jonathan Sullivan 2012-12-21

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https://ww2.mathworks.cn/matlabcentral/answers/57181-passing-varagin-and-getting-inputname-to-work-properly#answer_69161

编辑：Jonathan Sullivan 2012-12-21

在 MATLAB Online 中打开

You could use "evalin"

In your example it would be something like:

function struct = temp( varargin )
    struct = parseInputs( varargin{1:end} )
end
function struct = parseInputs( varargin )
    for ii = 1:length(varargin)
        struct.(['name' num2str(ii)]) = evalin('caller',['inputname(' num2str(ii) ');']);
    end
end