String scalar or character vector must have valid interpreter syntax

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Gookki Jeong 2020-7-31

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https://ww2.mathworks.cn/matlabcentral/answers/573190-string-scalar-or-character-vector-must-have-valid-interpreter-syntax

评论： Walter Roberson 2020-7-31

采纳的回答： Adam Danz

Rx(1)= "(cos(seta)-0.3 * sin(seta)) * Rx_" ;

Ry(1)= "(0.3*cos(seta) + sin(seta)) * Ry_";

there are my variable and

I wrote the plot title like this

title(Rx(1)+" + "+Ry(1));

but I recieve this error message,' String scalar or character vector must have valid

interpreter syntax' . How can I fix it?

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采纳的回答

Adam Danz 2020-7-31

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编辑：Adam Danz 2020-7-31

在 MATLAB Online 中打开

You probably want something like

title(sprintf('%.2f + %.2f', Rs(1), Ry(1)))

See sprintf for more info.

Update

Set interpretter to 'none',

title(Rx(1)+" + "+Ry(1),'Interpreter','none');

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Adam Danz 2020-7-31

I didn't see that the Rx and Ry values had quotes. In the furture, it would be helpful if you format your code using the [>] button in the question/comment editor.

I've updated my answer with the solution.

Walter Roberson 2020-7-31

Interpreter none, or use \_

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MATLAB Programming Functions Argument Definitions

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