How to fill a cell with function handles using iteration numbers?

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ejk
ejk 2020-8-5
评论： ejk 2020-8-5
I am trying to create N functions that are all extremely similar, except they use different constants from an N sized array.
I have a cell G = {}, but I'm not sure how to create a for loop that would set G{1} = @(x) c(1)*x (this is an example, not the actual function), where c is an array containing the constants cooresponding to each function.
I tried placing G{k} = @(x) c(k)*x and iterating k from 1 to N, but that creates functions that contain k, and not the actual iteration number 1, 2,...N.

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Steven Lord
Steven Lord 2020-8-5
c = (1:10).^2;
G = cell(size(c));
for whichElement = 1:numel(c)
G{whichElement} = @(x) c(whichElement)*x;
end
Yes, when you display each element of G the expression that gets displayed will include whichElement. But the anonymous function remembers the value whichElement (and c for that matter) had when it was defined and will use those values when the anonymous function is evaluated.
G{7}(5) % 49*5 = 245

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