Checking a matrix for duplicates in specific row, removing the respective columns

Question

Claudius Simon Appel 2020-8-6

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/576019-checking-a-matrix-for-duplicates-in-specific-row-removing-the-respective-columns

评论： Claudius Simon Appel 2020-8-6

采纳的回答： Bruno Luong

在 MATLAB Online 中打开

So, I try to explain this.

I have a two-row matrix of values, [x;y], f.e.

x=[1 2 2 3 4 5 6 6 7]
y=[1 2 3 4 5 6 7 7 8]

being merged into the matrix:

d= [1 2 2 3 4 5 6 6 7;
    1 2 3 4 5 6 7 7 8]

I then want to check this matrix for repeats in the first row & remove the respective columns, while saving the x values of the columns being removed as a seperate vector. So Output should be something like:

d=[1 3 4 5 7;
   1 3 4 5 8]
x_cut=[2 6]

It should be noted that this would have to scan for multiple repeats of different values, as shown above.

Thank you.

Have a great day & stay safe

Claudius Appel

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Answer 1

Bruno Luong 2020-8-6

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https://ww2.mathworks.cn/matlabcentral/answers/576019-checking-a-matrix-for-duplicates-in-specific-row-removing-the-respective-columns#answer_476017

编辑：Bruno Luong 2020-8-6

在 MATLAB Online 中打开

d= [1 2 2 3 4 5 6 6 7;
    1 2 3 4 5 6 7 7 8]
dd = diff([nan,d(1,:),nan])==0;
remove = dd(1:end-1) | dd(2:end)
x_cut = unique(d(1,remove),'stable')
d(:,remove) = []

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Bruno Luong 2020-8-6

编辑：Bruno Luong 2020-8-6

在 MATLAB Online 中打开

d= [1 2 2 3 4 5 6 6 7;
    1 2 3 4 5 6 7 7 8]
dd = diff([nan,d(1,:),nan])==0;
remove = dd(1:end-1) | dd(2:end);
cut = d(:,remove)
keep = d(:,~remove) % rename keep to d if you like

Or if yoy want to get cut from x_cut

dd = diff([nan,d(1,:),nan])==0;
remove = dd(1:end-1) | dd(2:end)
x_cut = unique(d(1,remove),'stable')
cut = d(:,ismember(d(1,:), x_cut))
d(:,remove) = []