Function ranges in Matalb
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Hello everybody,
I am trying to use Gui matlab to determine the output of a function in two different ranges which are compared with user-entered values. I set the axis Z as
Z=0.000001:500;
The I used the entered values by user in calculations:
Z03= (4.*E.^1.6)/(r3.*0.8862269);% E and r3 are given by the user
Z04= (4.*E.^1.6)/(r4.*0.8862269);% E and r4 are given by the user
delat3=0;
delat4=0;
p3=-exp((-(Z-delat3)./Z03).^2);
p4=-exp((-(Z-delat4)./Z04).^2);
After that I defined the function's ranges as follows:
for i=1:numel(Z)
if Z(i)<=d3 % d3 is given by the user
P2L=(p3.*(2*(Z-delat3)./Z03))./((Z03).^2);
elseif (Z(i) > d3) && (Z(i) < d4) % d4 is given by the user
P2L=(p4.*(2*(Z-delat4)./Z04))./((Z04).^2);
end
end
and plot the results by
plot(Z, P2L,'linewidth',2)
When I press 'Plot' I got this error
Operands to the || and && operators must be convertible to logical scalar values.
Would you please help me to slove this error?
Thanks in advance,
Ahmed
6 个评论
dpb
2020-8-17
编辑:dpb
2020-8-17
Well, whenever it was that the code posted before was run, the error message is clear that wasn't a scalar.
Use the debugger to see in context.
But, as written there's no need for the & operator anyways...and it is "&" you would want here, not "&&" if did need the compound test.
回答(1 个)
Walter Roberson
2020-8-21
for i=1:numel(Z)
if Z(i)<=d3 % d3 is given by the user
P2L(i)=(p3.*(2*(Z(i)-delat3)./Z03))./((Z03).^2);
elseif (Z(i) < d4) % d4 is given by the user
P2L(i)=(p4.*(2*(Z(i)-delat4)./Z04))./((Z04).^2);
else
P2L(i) = nan; %undefined outside the range given
end
end
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