Why a linear model cannot be plotted in app designer?

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Hi,
I am using fit(x, y, 'poly1') in app designer.
a = linspace(0,10,10)'
b = linspace(0,20,10)'
[fitline,gof] = fit(a, b, 'poly1' )
plot(app.name, fitline, a, b)
When I try to plot the linear model and the vectors a and b I am getting the following error:
Error using plot
Data must be numeric, datetime, duration or an array convertible to double.
I tried it the same in my commad window and there was no error there. Any idea what is causing it in app designer?
Thanks
Hugo

采纳的回答

Adam Danz
Adam Danz 2020-8-19
编辑:Adam Danz 2023-9-18
This issue has been fixed in MATLAB R2023b
Starting in MATLAB R2023b, provide the axis handle as the first input to plot the fit line in your app's axes.
plot(app.UIAxes, fitline, a, b)
Workaround prior to R2023b: create plot externally, then copy to AppDesigner axes
Prior to R2023b, plotting a cfit object is not supported with uifigures (e.g. AppDesigner; see Graphics Support in App Designer). Even if it were supported, for whatever reason there is no way to specify an axis handle when plotting a cfit object, although that problem isn't difficult to solve.
For more info see
Workaround: You can plot the fit object in an external, temprary figure, copy its content to the App's axes, and then delete the temporary figure.
% Create uifigure and uiaxes to mimic AppDesigner
app.UIFigure = uifigure();
app.UIAxes = uiaxes(app.UIFigure);
% Plot cfit object externally.
a = linspace(0,10,10)';
b = linspace(0,20,10)';
[fitline,gof] = fit(a, b, 'poly1');
fig = figure('Visible','off'); % you may want to set this to "on" to see what's happening
ax = axes(fig);
h = plot(fitline,a,b);
% Copy content of temp axes to app designer
hApp = copyobj(h, app.UIAxes);
% You'll need to recreate the legend since it can't be independently copied
lh = legend(app.UIAxes);
% Delete temp figure
delete(fig)
  7 个评论
Adam Danz
Adam Danz 2023-9-19
Thanks for the explanation @Mohd Aaquib Khan. It doesn't sound right. I'm creating a regular figure using the figure function as opposed to the uifigure function. Furthermore, the figure is generaged with the visible property set to off so you should never see the figure appear.
If you are still having trouble, you could share the full callback function so I can see what's going on.
Mohd Aaquib Khan
Mohd Aaquib Khan 2023-9-20
编辑:Mohd Aaquib Khan 2023-9-20
Thank you for your time @Adam Danz,
Since you are investing your time, I have created a new question request for it so that you get some credit for it.
I am using pretty much the same code as you have provided.

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