Counting number of unique elements in a matrix

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I have a matrix, 2xT. It contains value PAIRS that are unique and some that are repeated.
I would like to order the matrix by the pairs that occur the most frequently.
myData = randi([0 20], [10000 2]); %make up some data
[C,ia,ic] = unique(myData,'rows');
such that %isequal(C(ic,:), myData) =1. Great.
I now try and work out the ordering
[nOccurances IX] = sort(histc(ic, 1:length(ic)), 'descend');
This gives nOccurances which looks sensible.
Now I try and output:
myDataSorted = myData(ic(IX),:);
The output value is just wrong.
Where have I gone wrong? Thank you!!
  2 个评论
Matlab2010
Matlab2010 2013-1-10
编辑:Matlab2010 2013-1-10
SOLVED:
myData = randi([0 20], [10000 2]); %make up some data
[C,ia,ic] = unique(myData,'rows');
[nOccurances IX] = sort(histc(ic, 1:length(ic)), 'descend');
idY = (nOccurances==0);
nOccurances(idY) = [];
IX(idY) = [];
myDataSorted = [nOccurances C(IX,:)];
Matt J
Matt J 2013-1-10
Then you should either delete the question or submit then Accept your own solution as an Answer

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