Index exceeds the number of array elements (9).

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Ralph 2020-8-28

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评论： Ralph 2020-8-28

[row,c]=size(x); 
total_frames=row/9;
k=1;
i=5;
aa=rem(row,P+1); % in this case P+1=9;
last_index=row-aa;
for i=5:9:last_index %runs for tatal number of samples in signal
   x =[x(i)-1, x(i)-2, x(i)-3, x(i)-4, x(i), x(i)+1, x(i)+2, x(i)+3, x(i)+4];   
   j=x(i);

I want this code to print the above 9 samples in J variable but it throws an error "Index exceeds the number of array elements (9)".

   
    for r=0:(P/2)-1  % Sumation loop from formula        
     neighbour=x(i + (r-(P/2)));
     center=x(i);     
     if(neighbour > center+ thresh)
         b_left(r+1)=1;
     elseif( (neighbour > center-thresh) && (neighbour < center+thresh))
         b_left(r+1)=0;
     elseif (neighbour < center-thresh)
         b_left(r+1)=-1;    
     end 

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Answer 1

KSSV 2020-8-28

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The error is simple. You are trying to extract more than the number of elements present in the array.

A = rand(5,1) ; 
A(1)  % no error
A(5)  % no error
A(end) % no error
A(6)   % error, because there is no sixth element present in A. Only five elements. 

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Ralph 2020-8-28

Basically my "x" variable contain 9 samples the loop start from 5 and I want to return all elements before and after 5 so can you please tell me how to return these 9 values in variable j.

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