How to resolve Horzcat error (narrowed it down to one value in the for loop) and output for loop correctly.

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sree chak
sree chak 2020-9-3
回答： David Hill 2020-9-3
I have the following code. What I want the inner loop to do is calculate DipoleParam = x,y,z,mx,my,mz and put it into the row of a new matrix...i.e. by the end of the inner loop, I should have a 3*7 matrix. Then by the end of the outer loop, I should have two of these 3*7 matrices.
But I keep getting a horzcat error primarily because my c value is always showing as a 1*1...rather than a 1*n....I am just trying to see what the best way to resolve this error is.
Q = 2
Nini = 3
for q = 1:Q
for n = 1:Nini
Range = 2*pi*(rand(n,1));
Radius = 20*sqrt(rand(n,1));
x = 0 + Radius.*cos(Range);
y = 0 + Radius.*sin(Range);
z = -5 +(10)*rand(n,1);
mx = 2000*rand(n,1);
my = 2000*rand(n,1);
mz = 2000*rand(n,1);
c = 5-n
DipoleParam = [Dipolex Dipoley z Mx My Mz c]
end
end

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回答（1 个）

David Hill
David Hill 2020-9-3
Seems to be lots of problems with your code. I likely don't understand everything.
for q = 1:2%I don't see a need for an inner loop
Range = 2*pi*(rand(3,1));%generates 3x1 array
Radius = 20*sqrt(rand(3,1));
x = 0 + Radius.*cos(Range);
y = 0 + Radius.*sin(Range);
z = -5 +(10)*rand(3,1);
mx = 2000*rand(n,1);%3x1 array
my = 2000*rand(n,1);
mz = 2000*rand(n,1);
c = 5-n%I have no ideal what c is suppose to be but it must be a 3x1 array
DipoleParam{q} = [Dipolex Dipoley z Mx My Mz c]%what are Dipolex and Dipoley? not defined anywhere...Is Mx, My, Mz suppose to be mx,my,mz?
end

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