Counting every other number in a list
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Howdy.
I have a matrix
mylist = [1:10]
I need to count every other number in this matrix
I can't use the odd or even distinguishing tests such as...
for i = 1:length(mylist)
if rem(mylist(i),2) ~= 0;
eo_total = eo_total + 1
end
end
Because this only counts the odd numbers in my for loop. So if I had a matrix
mylist(2) = [ 2 4 6 8 10]
eo_total = 0 instead of 2
any ideas?
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the cyclist
2020-9-12
I'm not sure what you mean by "count" them, but the following vector will store every other element from mylist, starting with the first one:
out = mylist(1:2:end)
2 个评论
the cyclist
2020-9-12
Oh. Then it's probably more efficient to do
ceil(numel(mylist)/2)
Then you don't need to create a second vector.
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