comparing table values using isequal

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Jakub Steiner
Jakub Steiner 2020-9-15
评论： Cris LaPierre 2020-9-15
Hi,
I have a table M. The second column contains either the letter 's' or letter 'f'.
I would like to put all the rows with the letter 'f' in the second column into a new table A with the following code
pocet_radku = height(M);
j=1;
for i=1:pocet_radku
TF = isequal ("M(i,2)",'f')
if TF == 1
A(j,:)= M(i,:);
j = j+1;
else
end
end
Unfortunatelly, the isequal function return only zeros. Any idea why? In there syntax error that I'm not aware of?
Testing in a command window:
>> isequal ("M(180,2)",'f')
ans =
logical
0
>> M(180,2)
ans =
table
Var2
_____
{'f'}
Thanks a lot for any answers

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采纳的回答

Cris LaPierre
Cris LaPierre 2020-9-15
编辑：Cris LaPierre 2020-9-15
This can be done much simpler. Try something like this.
A = M(M{:,2}=="f",:);
  2 个评论
Jakub Steiner
Jakub Steiner 2020-9-15
Nice! Works as well and without my clumsy cycles.
Thanks a lot!
Cris LaPierre
Cris LaPierre 2020-9-15
This can be made even simpler by using the variable name:
A = M(M.Var2=="f",:);

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更多回答（2 个）

Fangjun Jiang
Fangjun Jiang 2020-9-15
编辑：Fangjun Jiang 2020-9-15
try TF = isequal (M.Var2{i},'f')
BOB MATHEW SYJI
BOB MATHEW SYJI 2020-9-15
Instead of
TF = isequal ("M(i,2)",'f')
try,
TF = strcmp (M.2nd_variable,'f')

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