open file in notepad via gui

2011 4 21
3 个回答
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0 个投票

Hellow, i search a method to open a file in notepad or another simple txt reader from a gui. So my code generates a ascii file and if i push a button the file have to open notepad. my ascii file is: a = sinogram.sin;
if have found open('a');
but then it opens in matlab itself. Thx

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 采纳的回答

Paulo Silva
Paulo Silva 2011-4-21

3 个投票

Example:
!notepad C:\Program Files\MyFolder\textFile.txt
Just replace that path with your own.

更多回答（2 个）

Fiboehh
Fiboehh 2011-4-21

0 个投票

Okj that works but know i want to pick a .sin file out of a load window. You know how to do that? i tried
m = uigetfile('*.sin','Select the .sin-file');
!notepad m
but that didnt work! I need something to read out the file and then to open it. Thx a lot

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Paulo Silva
Paulo Silva 2011-4-21
eval(['!notepad ' m])
Paulo Silva
Paulo Silva 2011-4-21
The way you call uigetfile is wrong
[FileName,PathName] = uigetfile('*.sin','Select the .sin-file')
eval(['!notepad ' PathName FileName])
Paulo Silva
Paulo Silva 2011-4-21
And another way for those who hate the eval function
system(['notepad ' PathName FileName])

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Fiboehh
Fiboehh 2011-4-21

0 个投票

Okj thx so much paulo,
[FileName,PathName] = uigetfile('*.sin','Select the .sin-file')
eval(['!notepad ' PathName FileName])
works, but when the load window opens and if i click on annulate, there opens an empty notepad window and thats not the goal :) hope you have something to fix that.

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Paulo Silva
Paulo Silva 2011-4-21
[FileName,PathName] = uigetfile('*.sin','Select the .sin-file')
if ischar(FileName)
%disp('file selected')
eval(['!notepad ' PathName FileName])
else
%disp('user canceled')
end

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