array dimensions must match in binary op

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AS
AS 2020-9-17
评论： Walter Roberson 2020-9-17
I am trying to perform this code 3D data but I am getting this error " array dimensions must match in binary op". To solve this error can anybody help me please.
data_p=permute(data,[3,2,1]); % data
for kk=1:5 % outer loop
for m=1:niter % number of iteration
for i=1:1801
for j=1:10
for ii=2:k
D(i,:,j)=data(i,:,j)-C(:,:,j);
D=cumsum(sqrt(dot(D,D,1)));
if D(end)==0
C(:,ii:k,j)=data(:,ones(1,k-ii+1),j);
return
end
C(1:k,:,:)=data(find(rand<cumsum(D)./sum(D),3),:,:);
C_p=permute(C,[3,2,1]);
[~,L]=max(bsxfun(@minus,2.*real(C.*data_p),dot(C_p,C_p).'));
end
end
end
end
end
Error:
Array dimensions must match for binary array op.
Error in test5(line 51)
[~,L]=max(bsxfun(@minus,2.*real(C.*data_p),dot(C_p,C_p).'));
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AS
AS 2020-9-17
I have used C_p.*data_p this also as you mentioned, but same error is showing
Walter Roberson
Walter Roberson 2020-9-17
When you multiply something whose dimensions are 3, 3, and 10, by something whose dimensions are 3, 10, and 1801, then what size of output are you hoping for? Something whose dimensions are 3, 3, 10, and 1801 -- a 4 dimensional result?

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