Index in position 2 is invalid. Array indices must be positive integers or logical values.

Question

Joshua Scott 2020-9-22

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/597601-index-in-position-2-is-invalid-array-indices-must-be-positive-integers-or-logical-values

编辑： DGM 2022-2-2

Hi. Im a newb. Im struggling to figure this part out. From what I can see, none of my indexes are negative. How can I fix this?

for iter=J:-1:1  % loop over 
    iter;
    for indY=1:dimY
        V(:, indY)=interp1(K, V(:, indY), K_prime, 'linear', 'extrap');
    end
    for ik=1:dimK     % loop over all current cake sizes
        for ik2=1:dimK
            c=K(ik)*(1+r)+Y(iter)-K(ik2);
            if c>0 
                U(ik, Y(iter), K(ik))=((c)^(1-eta)-1)/(1-eta)+beta*transY(indY, :).*(V(ik2, :)');
            else
                U(ik2)=-1e10;
            end
        end
        [V(ik, iter), ind]=max(U);     % optimizing over size of next period cake
        A(ik, iter)=K(ind);
        A_ind(ik, iter)=ind;
        C(ik, iter)=K(ik)*(1+r)+Y(iter)-K(ind);
    end
end

Im assuming the line I have bolded is the issue, but Im not entirely sure.

Thank you for your help!

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Answer 1

Star Strider 2020-9-22

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/597601-index-in-position-2-is-invalid-array-indices-must-be-positive-integers-or-logical-values#answer_498199

My guess is that the problem is using ‘Y(iter)’ and ‘K(ik)’ as indices in that assignment. They may not be integers greater than 0, or logical values. All the other array references appear to be correct