Horizontal asymptote of exponential decay

1 次查看（过去 30 天）
Lynn Knoblauch
Lynn Knoblauch 2013-1-25
Hello, does anyone know how to find the horizontal asymptote of an exponential decay function?

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2013-1-25
Evaluate the function at infinity.
  6 个评论
显示 4更早的评论
Lynn Knoblauch
Lynn Knoblauch 2013-1-30
I would never of thought of this and this does make more sense. Thank you for your response. MUCH APPRECIATED!
Walter Roberson
Walter Roberson 2013-1-30
The diff() should logically be fitted with a difference of x coordinates, but since your x is in the exponent, A*exp(B*x)+C, subtracting for two different x... (A*exp(B*x1)+C) - (A*exp(B*x2)+C) = A*(exp(B*x1)-exp(B*x2)) and then you do not get nice clean log(exp(B*x)) -> B*x like I was thinking when I proposed the above.
I think a nonlinear least-squares is going to be needed.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Least Squares 的更多信息

标签

尚未输入任何标签。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by