Step function with a ramp. Error in the creation of the ramp

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I am trying to create a ramp which is a part of a step function in order to plot it.
x=1e-6:1e-6:L;
for i=1:10
bl(i)=(2*i-1)*9.35e-4+(i-1)*8e-5;
bu(i)=(2*i-1)*9.35e-4+i*8e-5;
I(x>=bl(i) & x<bu(i))=(i-1)*1.26e-2+150.*(x-bl(i)); % Current in part b of the unit cell
end
But I get this error:
In an assignment A(I) = B, the number of elements in B and
I must be the same.
Do you know the solution?
  1 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2013-1-27
What is the initial value of I. What is the expected value of I ?
Can you explain what do you want to achieve?

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采纳的回答

Matt J
Matt J 2013-1-27
idx=(x>=bl(i) & x<bu(i));
I(idx)=(i-1)*1.26e-2+150.*(x(idx)-bl(i));
  7 个评论
Matt J
Matt J 2013-1-28
Here's a somewhat lazy way of doing it,
t=linspace(0,12,1e4);
f=@(x) 5.*(x<=5) +x.*(x>5 & x<=10) + 10*(x>10);
plot(t,f(t)); ylim([4,11])

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更多回答(2 个)

Image Analyst
Image Analyst 2013-1-27
编辑:Image Analyst 2013-1-27
Have you considered linspace() instead?
bl = linspace(9.35e-4, 19*9.35e-4+9*8e-5, 10)
bu = linspace(9.35e-4, 19*9.35e-4+10*8e-5, 10)
output = linspace(0, 9*1.26e-2, 10)+150*(x-bl)
indexesToSet = x>=bl & x<bu % Only set those elements satisfying this.
I(indexesToSet) = output(indexesToSet)

Giorgos Papakonstantinou
编辑:Giorgos Papakonstantinou 2013-1-27
I didn't know about linspace. I would definitely try it out. Thank you both!
  1 个评论
Image Analyst
Image Analyst 2013-1-27
It's just a more MATLAB-ish way of doing things since it avoids a loop, though with only 10 iterations, looping is definitely not a bottleneck. If you had tens of millions of iterations, it might make a noticeable effect.

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