why the image has no color in this code?

2 次查看（过去 30 天）

Isee You 2013-1-28

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/60159-why-the-image-has-no-color-in-this-code

when i run this code the image with title""('rgbimage inside if');"" show as binary image .id don't know why?? here is the code and u can download the mat file from "u.mat" http://www.mediafire.com/?tf3ef09n4it3aa2 and "var.mat" http://www.mediafire.com/?ovn31e28d51eb1c

filename = 'u.mat';
matObj = matfile(filename);
moving = matObj.u;
I2 = matObj.im1;
filename2 = 'var.mat';
matObj = matfile(filename2);
storedColorMap = matObj.storedColorMap;
figure, imshow(moving,[]), title('binary gradient  ');impixelinfo;
[rrr ccc] = size(I2); 
moving = imresize(moving, [rrr ccc]);
rgbImage = moving;
  % Read in image into an array.
  [rows columns numberOfColorBands] = size(rgbImage); 
  % If it's monochrome (indexed), convert it to color. 
  % Check to see if it's an 8-bit image needed later for scaling).
  if strcmpi(class(rgbImage), 'uint8')
    % Flag for 256 gray levels.
    eightBit = true;      
  else
    eightBit = false;       
  end
if numberOfColorBands == 1
    if isempty(storedColorMap)
      % Just a simple gray level image, not indexed with a stored color map.
      % Create a 3D true color image where we copy the monochrome image into all 3 (R, G, & B) color planes.
      rgbImage = cat(3, rgbImage, rgbImage, rgbImage);
            figure,imshow(rgbImage);title('rgbimage inside if');
    else
      % It's an indexed image.
      rgbImage = ind2rgb(rgbImage, storedColorMap);
           figure,imshow(rgbImage,[]);title('rgbimage inside esle');
      % ind2rgb() will convert it to double and normalize it to the range 0-1.
      % Convert back to uint8 in the range 0-255, if needed.
      if eightBit
        rgbImage = uint8(255 * rgbImage);
      end
    end
end

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Walter Roberson 2013-1-28

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/60159-why-the-image-has-no-color-in-this-code#answer_72709

You show "moving" as a "binary gradient". Then you convert "moving" to an RGB image by splicing three copies of it together, into the RGB planes. The locations in the binary array "moving" that were 0 will become [0,0,0] (black) and the locations in the binary array "moving" that were 1 will become [1,1,1] (white), so the result will still look like a binary image.

11 个评论
显示 9更早的评论隐藏 9更早的评论

Image Analyst 2013-1-29

A floating point RGB image would be a color image with the values not being integers in the set 0, 1, 2, 3, 4, ...255. For example an image that had all kinds of continuous values ranging from -34.1147 to +290.2591. Casting to uint8 should work unless all the values are less than 0 and more than 255.

Isee You 2013-1-29