Find equal elements in an array and average the corresponding values

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Hello, I have a cell array A{2, 6} like the following
[-0.27,11.53,-2.82] [0.01,11.72,-3.27] [-0.04,11.56,-2.87] [-0.01,11.73,-2.62] [-0.01,11.73,-2.62] [0.10,11.58,-3.22]
128151x3 double 55009x3 double 84858x3 double 92417x3 double 40318x3 double 65249x3 double
and I would like to average the values ​​of A{2, x} if 2 or more cells in A {1, x} are equal. Based on the example above I would like to have a cell array A{2, 5} like the following:
[-0.27,11.53,-2.82] [0.01,11.72,-3.27] [-0.04,11.56,-2.87] [-0.01,11.73,-2.62] [0.10,11.58,-3.22]
128151x3 double 55009x3 double 84858x3 double mean (92417x3 double,40318x3 double) 65249x3 double
How can I do it. Thank you very much!

回答(1 个)

KSSV
KSSV 2020-10-12
编辑:KSSV 2020-10-12
Let A and B be your matrices of size 92417x3, 40318x3 respectively. First you need to get them to the same dimension to find the mean. For this, you have to do interpolation.
B_new = A ;
B_new(:,3) = scatteredinterpolant(B(:,1),B(:,2),B(:,3),A(:,1),A(:,2)) ;
themean = B ;
themean(:,3) = (A(:,3)+B(:,3))/2 ;
  3 个评论
KSSV
KSSV 2020-10-12
That can be done with ease...you want to find mean..if the first and last point matches??
Riccardo Rossi
Riccardo Rossi 2020-10-12
I want to find the mean of the values in the "second row" if two or more point of the "first row" are equal

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