Making consecutive 1s and 0s as a seperate element

a = [1 1 0 0 0 1 1 1 1 0 1 1];
idx = [1 find(diff(a)~=0)+1 numel(a)+1];
C = cell(numel(idx)-1, 1);
for i = 1:numel(C)
    C{i} = a(idx(i):idx(i+1)-1);
end

Result

>> C{1}
ans =
     1     1
>> C{2}
ans =
     0     0     0
>> C{3}
ans =
     1     1     1     1
>> C{4}
ans =
     0
>> C{5}
ans =
     1     1

3 个评论
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Ameer Hamza 2020-10-17

Try the updated code.

Jetty Rakesh Aditya 2020-10-17

@Ameer Hamza thanks a lot!

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Answer 2

KSSV 2020-10-17

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/616698-making-consecutive-1s-and-0s-as-a-seperate-element#answer_516308

Refer this link: https://in.mathworks.com/matlabcentral/answers/104614-grouping-continuous-nonzero-in-a-row-vector

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Answer 3

Adam Danz 2020-10-17

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/616698-making-consecutive-1s-and-0s-as-a-seperate-element#answer_516503

编辑：Adam Danz 2020-10-17

在 MATLAB Online 中打开

a = [1 0 0 0 1 1 1 1 0 1];
consecGroups = findgroups(cumsum([true, diff(a)~=0]));
b = arrayfun(@(g){a(consecGroups==g)},1:max(consecGroups));
% Show results
celldisp(b)
 
b{1} =
 
     1

b{2} =
 
     0     0     0

b{3} =
 
     1     1     1     1

b{4} =
 
     0

b{5} =
 
     1