I have matrix A, calculate null(A) but then A*null(A) doesn't give me 0?

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%a) The traffic flow is an overdetermined system 12 variables to 9 equations
A = [-1 0 0 0 0 0 0 1 0 0 0 0;
1 1 0 0 0 0 0 0 0 0 -1 0;
0 -1 1 0 0 0 0 0 0 0 0 0;
0 0 -1 -1 0 0 0 0 0 0 0 1;
0 0 0 1 1 0 0 0 0 0 0 0 ;
0 0 0 0 1 1 0 0 -1 0 0 0;
0 0 0 0 0 -1 1 0 0 0 0 0;
0 0 0 0 0 0 -1 -1 0 1 0 0;
0 0 0 0 0 0 0 0 1 -1 1 -1];
b = [0; 150; 20; -410; 180; 210; 80; -230; 0];
%b)Gives five free variables, so there is not a unique solution,
%meaning the traffic flow depends in other intersects
x = linsolve(A,b);
%e)
nullspace = null(A) %Three vectors in the nullspace
nullVector = A* nullspace(:,1) %Shouldn't this give me zero vector?
I am wondering if I calculate null(A) and tree null vectors:
0.0939 0.3560 -0.3875
-0.1103 0.2839 0.4184
-0.1103 0.2839 0.4184
-0.0000 0.0000 0.0000
0.0000 -0.0000 -0.0000
0.4610 -0.0825 0.2202
0.4610 -0.0825 0.2202
0.0939 0.3560 -0.3875
0.4610 -0.0825 0.2202
0.5549 0.2734 -0.1674
-0.0164 0.6399 0.0309
-0.1103 0.2839 0.4184
Shouldn't that mean A*nullspaceVector = 0 ?
But nullVector = A* nullspace(:,1) gives me:
nullVector =
1.0e-15 *
0.0139
-0.1180
0.3053
-0.3053
-0.0714
0.2776
-0.1665
0.2220
0.0971
  1 个评论
Bruno Luong
Bruno Luong 2020-10-21
编辑:Bruno Luong 2020-10-21
1.0e-15 * somenumber is considered as 0 numerically in floating point calculation.
Illustration of the same thing with simpler example
>> x=[3 4];
>> y=null(x)
y =
-0.8000
0.6000
>> x*y
ans =
-4.4409e-16

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回答(1 个)

Steven Lord
Steven Lord 2020-10-21
Note that the description of the output argument on the documentation page for the null function does not include the character 0. It says that Z satisfies two properties, the key one of which for this question is "A*Z has negligible elements."
I would call 1e-15 or 1e-16 negligible relative to the elements in your matrix.

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