Infinite series for pi

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AngelsaAtWar
AngelsaAtWar 2013-2-6
Hi I was wondering how I would go about writing a program for this infinite series of pi, so that the script works and I am would be able to plot a graph form it? http://upload.wikimedia.org/math/3/7/0/3706d96d8b2b4281a22700f2b642a5ad.png
I am new to Matlab Student version and having a hard time with the series problems. than you all and have a great day

回答(1 个)

Youssef  Khmou
Youssef Khmou 2013-2-6
编辑:Youssef Khmou 2013-2-7
hi, You can use loops to get the value pi=22/7, so it is an infinite serie, you specify in your software the format short to show 4 digits after the decimal point
example :
format short
f=2.6589
You implement the loop :
% Infinite series for PI
PI=0;
%tolerance=1e-3;
n=1;
N=6351;
v=zeros(N+1,1);
for n=0:N
PI=PI+4*(((-1)^n)/(2*n+1));
v(n+1)=PI;
%n=n+1;
end
PI=PI;
figure, plot(v)
figure, plot(v(1:40)), hold on, plot(0:0.1:40,pi,'r-')
  6 个评论
ChristianW
ChristianW 2013-2-7
Your x-axis is not n , its n+1 , the v-indices. (v(1) = v(n=0))
Youssef  Khmou
Youssef Khmou 2013-2-7
@Christian : improve the code !

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