How to put for loop outcome into 1 column in right order

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MadjeKoe
MadjeKoe 2020-10-26
评论： MadjeKoe 2020-10-26
Hi guys, I made the following for loop where I calculated the response errors for each target. Now instead of putting them in a new matrix in 4 different columns, I want to put the error responses (err) as 1 column in the old matrix (res), in the correct order (so each error response matches its trials). Can somebody explain how to do this?
res = S.res;
trials = res(:,1);
targets = res(:,7);
responses = res(:,8);
oria = [3,4,5,6];
tar = [1,2,3,4];
num = numel(oria);
out = cell(1,num);
for k = 1:num
tarsel = targets==tar(k);
resp = responses(tarsel);
orib = res(tarsel,oria(k));
err = resp - orib;
err(err<-90) = err(err<-90)+180;
err(err>90) = err(err>90)-180;
out{k} = err;
end
out = [out{:}];

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回答（1 个）

Image Analyst
Image Analyst 2020-10-26
编辑：Image Analyst 2020-10-26
Can't you just say
res(:, 1) = err(:);
inside the loop? But every iteration will overwrite column 1 of course so not sure why, or if, you want that.
If that doesn't work, please attach your variables in a .mat file.
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Image Analyst
Image Analyst 2020-10-26
You can overwrite 2500 values of a longer vector with 2500 values of a shorter vector. Is that what you want to do? If so, why? And what do you want to do with the other 7500 values? Just leave them there as-is? Or erase them to zeros?
MadjeKoe
MadjeKoe 2020-10-26
No I do not want to overwrite them. I want each response error value to be in the row with its corresponding trial (in column res(:,9)). Because I had to calculate the errors based on 4 different targets, there are 4 different groups and I can't get the response errors to match the correct trial.

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