As there is a possibility to not enter the while statement, the solver will think that ‘y’ might not be assigned any value in the first branch. The code can be rewritten in a slightly different way as below. This code will run but can be further optimezed probably depending on the requirements.
function y = fcn(u)
a = 50000;
r = u*a;
count = 0;
if r < a
y = 0;
while count < a
if count <= r
y = 10;
end
count = count + 1;
end
else
y = 0;
end
