find the minimum value of x that corresponds to maximum value of theta
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Hello , I have :
x=30:0.5:300;
h=180;
hypot=sqrt(x.^2+h.^2);
phi=asind(h./hypot);
theta=90-phi;
Now , I want to find the minimum value of x that corresponds to maximum value of theta. How can I do this?
Thanks!
2 个评论
Sean de Wolski
2013-2-13
FYI, hypot() is a builtin function that does what you have above. So be careful not to overwrite it (and I recommend using it!)
x = 1:10;
y = 3
myHypot = hypot(x,y)
采纳的回答
Azzi Abdelmalek
2013-2-13
编辑:Azzi Abdelmalek
2013-2-13
[~,idx]=max(theta)
out=x(idx)
3 个评论
Azzi Abdelmalek
2013-2-13
How it works: Example
x=[1 2 3 4 5 6]
y=[10 20 1 21 15 2]
The maximum value of y is 21, it corresponds to index 4, which correspond in x to x(4)
[max_value,idx]=max(y)
out=x(idx)
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