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Am I correct in my approach regarding interpolation?

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tzaloupas
tzaloupas 2013-2-14
关闭： MATLAB Answer Bot 2021-8-20
Dear all
I have the vector
A={
[ NaN]
[ NaN]
[1.0877]
[1.0909]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
[ NaN]
};
and the date vector
D={'10/2008'
'11/2008'
'12/2008'
'1/2009'
'2/2009'
'3/2009'
'4/2009'
'5/2009'
'6/2009'
'7/2009'
'8/2009'
'9/2009'
'10/2009'
'11/2009'
'12/2009'
'1/2010'
'2/2010'
'3/2010'
'4/2010'
'5/2010'
'6/2010'
'7/2010'
'8/2010'
'9/2010'
'10/2010'
'11/2010'
'12/2010'
'1/2011'
'2/2011'
'3/2011'
'4/2011'
'5/2011'
'6/2011'
'7/2011'
'8/2011'
'9/2011'
};
and I am doing interpolation
xi = datenum(D, 'mm/yyyy');
z = interp1(xi(1:2:end),cell2mat(A(:,1)),xi);
Equivalently,
idx = ~isnan(cell2mat(A(:,1)));
z= interp1(xi(idx),cell2mat(A(idx,1)),xi);
Could you please verify that I am correct in my approach ?
thanks

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-2-14
v=cell2mat(A)
xi = datenum(D, 'mm/yyyy');
z = interp1(xi(3:4),v(3:4),xi,'spline');
  2 个评论
tzaloupas
tzaloupas 2013-2-14
Hi Azzi. thanks What is the difference between your approach and mine?Is this linear interpolation?
Satyam Gaba
Satyam Gaba 2018-8-24
No it's not a linear function. Spline interpolation can be used for polynomial interpolation for low degree polynomials as well as higher degrees.

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