hello Armando
I don't see what the first function is supposed to do ? output = input ? so what ?
for the second task, this should do the trick :
t = [1; 1; 1; 5; 5; 5; 2; 5; 5]
val1 = 1; % value to be replaced in t
val2 = 6; % value in replacement
output = Y(t)
% second function Y
function output = Y(input,val1,val2)
output = input;
ind = find(output==val1);
output(ind) = val2;
end
