save value into new variable after each iteration

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Maria Imdad 2020-11-4

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https://ww2.mathworks.cn/matlabcentral/answers/636055-save-value-into-new-variable-after-each-iteration

评论： J. Alex Lee 2020-11-5

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Hi everyone,

I am new to matlab, I have this one fuction, as a subpart of my code.

Here I am taking an initial string of 80 bits and after execution this loop, returns me 31 different strings as sub keys of the same length.

All I want is to save the value of these 31 keys in 31 different variables as "key1", "key2"....."key31".

This is my function:

    function key_out=updateKey(key, i) 
          sbox=[12 5 6 11 9 0 10 13 3 14 15 8 4 7 1 2];
          key_out=[key(62:80) key(1:61)];
          key_out(1:4)=dec2bin(sbox(bin2dec(key_out(1:4))+1),4);
          key_out(61:65)=dec2bin(bitxor(i, bin2dec(key_out(61:65))), 5); 
        disp(i);  
        disp('Output key');
          disp(key_out);
    end

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J. Alex Lee 2020-11-4

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Mario, shouldn't his function's only responsibility be to transform the "key" (a character array, not a string) based on the input i, and not have to worry about what's being done with the output? That decision can be made outside of the function.

Maria, Mario's suggestion assumes that you have some code that is using your function that is attempting to do what you described (serially name variables, which I agree with Mario is a VERY BAD idea).

To achieve Mario's suggestion without changing your updateKey function, you can define the character matrix variantkeysChAr as below. Or you can store it in a cell array, which I think would be easier and more generalizable

baseKey = sprintf('%d',randi(2,1,80)-1)
NumVariants = 31;
for i = NumVariants:-1:1
	variantkeysCell{i,1} = updateKey(baseKey, i);
	variantkeysChAr(i,:) = updateKey(baseKey, i);
end
function key_out=updateKey(key, i)
sbox=[12 5 6 11 9 0 10 13 3 14 15 8 4 7 1 2];
key_out=[key(62:80) key(1:61)];
key_out(1:4)=dec2bin(sbox(bin2dec(key_out(1:4))+1),4);
key_out(61:65)=dec2bin(bitxor(i, bin2dec(key_out(61:65))), 5);
% disp(i);
% disp('Output key');
% disp(key_out);
end

Mario Malic 2020-11-4

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My mistake, your solution is much better! Why did you use the reversed direction of loop, would it make a difference in the line below?

key_out(61:65)=dec2bin(bitxor(i, bin2dec(key_out(61:65))), 5);

J. Alex Lee 2020-11-5

The reverse loop is just to implicitly preallocate the arrays that are being populated in the loop.

It shouldn't make a difference in the line because you still are indexing consistently.

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