Solving a complicated equation in matlab

2013 2 18
2 个回答
回答已采纳
3 次查看（30 天）

0 个投票

I am trying to solve this equation in Matlab, I need to find the negative solution of this euation, here is what I do. syms x >> f=inline(cosh(3.7*x)+2.2*x^2-5*x-4); >> fzero(f,-2)
ans =
-0.351409329825233
I dont know what I am doing wrong?
Any help appreciated.

请先登录，再回答此问题。

 采纳的回答

Carlos
Carlos 2013-2-18
编辑：Carlos 2013-2-18

1 个投票

I think there is nothing wrong with your code. If I do
f(-0.351409329825233)
the answer is
ans =
-3.9968e-015
So -0.351409329825233 is a negative root of your equation.

类别

在 帮助中心 和 File Exchange 中查找有关 Mathematics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by