IFFT operation on the vector

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Hello,
I want to make an ifft operation on some vector. according to help of ifft, it do not require any multipcation constant. does this statement true all the time?

采纳的回答

Wayne King
Wayne King 2013-2-21
编辑:Wayne King 2013-2-21
As long as you do not zero pad, you should get back the original vector without using any scaling factor.
x = randn(10,1);
xdft = fft(x);
y = ifft(xdft);
max(abs(x-y))

更多回答(1 个)

Michael Adelman
Michael Adelman 2013-2-21
and if I zero pad, what constant I need to multiply?
  1 个评论
Wayne King
Wayne King 2013-2-21
Nothing, it will just add zeros at the end.
x = randn(10,1);
xdft = fft(x,16);
ifft(xdft)

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