How to add one scatter plor to another?

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Vasily Kozhevnikov
Vasily Kozhevnikov 2013-2-23
Hello,
I have two pairs of (x,y) arrays, say (x1,y1) and (x2, y2), they have equal length, but may be unordered. Also x1 set intersect x2. For example x1 = [0, 2, 4, 8, 1, 10] and x2 = [2, 9, 11, 13, 5, 7], corresponds to y1 = x1.^4 and y2 = sqrt(x2).
How to scatterplot y1+y2 sum on union of x1 and x2? Thanks.

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回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-2-23
编辑：Azzi Abdelmalek 2013-2-23
x=[x1 x2]
y=[y1 y2]
[val,idx]=sort(x);
new_x=val
new_y=y(idx)
plot(new_x,new_y)
  2 个评论
Vasily Kozhevnikov
Vasily Kozhevnikov 2013-2-23
x = [x1 x2] isn't union, and the last command will not plot sum
Azzi Abdelmalek
Azzi Abdelmalek 2013-2-23
编辑：Azzi Abdelmalek 2013-2-23
It's not clear, maybe this:
x=sort(unique([x1 x2]))
y1=x.^4;
y2=sqrt(x)
plot(x,y1+y2)

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Azzi Abdelmalek
Azzi Abdelmalek 2013-2-23
编辑：Azzi Abdelmalek 2013-2-23
%or you are looking for
x1 = [0, 2, 4, 8, 1, 10]
x2 = [2, 9, 11, 13, 5, 7],
y1=x1.^4;
idx1=find(ismember(x1,x2)) % find common values in x1 & x2
y1(idx1)=y(idx1)+sqrt(x1(idx1)) %add second function to common values
x2(ismember(x2,x1))=[] % remove common value from x2
y2=sqrt(x2)
[x,idx]=sort([x1 x2])
y=[y1 y2]
y=y(idx)
plot(x,y)
Vasily Kozhevnikov
Vasily Kozhevnikov 2013-2-24
Sorry, but in my task y1 is a list of values, but not an analytic function of x1. But now to my opinion I have a solution
x = union(x1, x2); f = interp1(x1, y1, x, 'cubic', 0) + interp1(x2, y2, x, 'cubic', 0); plot(x, f)
it may works
  1 个评论
Azzi Abdelmalek
Azzi Abdelmalek 2013-2-24
Vasily, in your question y1 and y2 are not a list of object, but functions of x1 and x2.

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