how to count the number of a specific value in a cell array and how to access the index of each value

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Dongyan Zhu
Dongyan Zhu 2020-11-18
编辑： Superficial 2020-11-18
Dear all,
i am now working with a cell array with fixed length:
VtStatus = {1,0,0,0,0,0};
and I also created 6 checkboxes to manage this cell array, e.g.: If I want to mark the checkboxes instead of the 3rd and the 5th, then this array goes like this:
VtStatus = {1,1,0,1,0,1};
Here comes the question: I want to know how many ''1'' are in this array and also the position of these ''1'' (e.g: I want to get the index of ''active checkboxes'' as a string '1-2-4-6' ). Which functions should I use?
Many thx!

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-11-18
编辑：Ameer Hamza 2020-11-18
If possible, use numeric array for this type of data. They will be much more efficient and easy to deal with. For cell array, you can try something like this
VtStatus = {1,1,0,1,0,1};
loccation = find([VtStatus{:}]);
num = numel(loccation);
active_checkboxes = strjoin(string(loccation), '-');
Result
>> loccation
loccation =
1 2 4 6
>> num
num =
4
>> active_checkboxes
active_checkboxes =
"1-2-4-6"

更多回答（2 个）

João Mendes
João Mendes 2020-11-18
To know the positions of the active checkboxes you can write:
active= find([a{:}]==1)
To know how many are active, i.e., how many '1's' exist, youc an write:
number=size(active,2)
It helps?
Superficial
Superficial 2020-11-18
编辑：Superficial 2020-11-18
Convert from a cell to a vector and it's easy.
VtStatus = {1,1,0,1,0,1};
vec=[VtStatus{:}] % Convert to a vector
inds=find(vec==1) % The index of each cell equal to one
str=num2str(inds) % You can convert inds to a string if you like
count = length(inds) % The number of cells equal to one
Gives the answers:
vec =
1 1 0 1 0 1
inds =
1 2 4 6
str =
'1 2 4 6'
count =
4

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