GA Toolbox maximization fucntion

2 次查看(过去 30 天)
In GA toolbox in Matlab we are getting fitness curve in form of minimization. How can I get maximization (fitness function) curve?
Can anyone help me in getting GA code for optimization?
this is my code
function [e] = mohfun(r)
dt = r(1);
ltt = r(2);
dss = r(3);
%% Data of cold fluid
tci=30; %Input temperature of cold fluid (C)
%tco=35; %Output temperature of cold fluid (C)
rowc=1000; %Density (kg/m3)
mioc=0.000797; %Viscosity (Pa s)
kc=.613; %Thermal conductivity (W/m K)
prc=5.83; %Prandtl number
cpc=4186; %Heat capacity (kJ/kg K)
mc=42; %Mass flow rate of cold fluid
vec=1.14; %velocity of cold fluid
%rec; %Reynold’s number OF COLD fluid
%hc; %hot stream of cold fluid
%ftc, %Darcy friction factor of cold fluid
%qc=input('Enter heat duty of cold fluid = '); %heat duty (W)
%% Data of hot fluid
thi=60; %Input temperature of hot stream (C)
%tho=45; %Output temperature of hot stream (C)
rowh=865.8; %Density (kg/m3)
mioh=0.023; %Viscosity (Pa s)
kh=0.141; %Thermal conductivity (W/m K)
prh=1205; %Prandtl number
cph=2000; %Heat capacity (kJ/kg K)
mh=17.2; %Mass flow rate
%veh=1.5; %velocity of hot fluid
%qh=input('Enter heat duty of hot fluid = '); %heat duty (W)
%pit=.005; %triangular pitch
%res %reynolds number (res) for shell side
%hs %hot stream of hot fluid
%% data of tube
%nt=input('Enter number of tube = '); %number of tube
dti=dt; %Tube inside diameter (m)
st=0.0043; %Tube thickness (m)
Rft=0.00042; %fouling factor
%dto %outer dimeter of tube
lt=ltt; %lt=input('Enter the length of tube = '); %Tubes length (m)
%% Data of shell
ds=dss; %Shell inside diameter (m)
np=1; %Number of tube passes
Rfs=0.0002; %fouling factor
%dh %hydraulic diameter
%% Equation
fprintf('dti %f \n ',dti)
fprintf('ltt %f \n ',ltt)
fprintf('dss %f \n ',dss)
dto=dti+st;
fprintf('dto %f \n ',dto)
%nt=mc/(rowc*(pi/4)*(dti^2)*vec);
v1=pi/4;
v2=dti^2;
v3=rowc*v2;
v4=v3*v1*vec;
nt=mc/v4;
ntt=nt*2;
fprintf('nt %f \n',nt)
%nt=nt1*2;
fprintf('ntt %f \n',ntt)
as=pi*dto*lt*nt*np;
fprintf('as %f \n',as)
rec = (rowc*vec*dti)/(mioc);
fprintf('rec %f \n',rec)
ftc = ((1.82*log(rec))-1.64)^(-2);
fprintf('ftc %f \n',ftc)
if rec < 2300
hc = (kc/dti)*(3.657+((0.0677*rec*prc*(dti/3.050))^1.33)/(1+0.1*prc*((rec*(dti/3.050))^0.3)));
elseif 2300 < rec && rec < 10000
hc = (kc/dti)*((1+(dti/3.050))^0.67)*(((ftc/8)*(rec-1000)*(prc))/(1+12.7*((ftc/8)^0.5)*((prc^0.667)-1)));
elseif rec > 10000
hc = (0.027)*(kc/dti)*(rec^0.8)*(prc^(1/3))*(mioc/mioc)^0.14;
end
fprintf('hc %f \n',hc)
%dh = (4*(0.43*pit^2-(pi*0.125*dto^2)))/(0.5*pi*dto);
%d1=ds^2-(dto^2*nt);
%d2=ds+(dto*nt);
%dh=d1/d2;
dh=(ds^2-(dto^2*nt))/(ds+(dto*nt));
fprintf('dh %f \n',dh)
f1=pi/4;
f2=f1*dh^2;
f3=f2*rowh;
veh=mh/f3;
fprintf('veh %f \n',veh)
res=(rowh*veh*dh)/mioh;
fprintf('res %f \n',res)
hs=(0.36*kh*res^0.55*prh^0.33)/dh;
fprintf('hs %f \n',hs)
%U = ((1/hs)+Rfs+(dto/dti)*(Rft+(1/hc)))^(-1);
U = ((1/hs)+Rfs+Rft+(1/hc))^(-1);
fprintf('U %f \n',U)
c1=mc*cpc;
fprintf('c1 %f \n',c1)
c2=mh*cph;
fprintf('c2 %f \n',c2)
if c1>c2
c_x=c1;
c_m=c2;
else
c_x=c2;
c_m=c1;
end
fprintf('c_m %f \n',c_m)
fprintf('c_x %f \n',c_x)
ntu= (as*U)/c_m;
fprintf('ntu %f \n',ntu)
cr=c_m/c_x;
fprintf('cr %f \n',cr)
%ef=1-exp(-cr^-1 * (1-exp(1-cr(ntu))));
e1=exp(-cr*ntu);
e2=1-e1;
e3=-cr^-1;
e4=e3*e2;
e5=exp(e4);
ef=1-e5;
%e7=1+e6;
%ef=1/e7;
e=ef;
fprintf('ef %f \n',ef)
tho=thi-ef*(thi-tci);
fprintf('tho %f \n',tho)
qh=mh*cph*(thi-tho);
fprintf('qh %f \n',qh)
tco=(qh/(mc*cpc))+tci;
fprintf('tco %f \n',tco)
lt= as/(pi*dto*nt);
fprintf('lt %f \n',lt)
end

采纳的回答

Walter Roberson
Walter Roberson 2020-11-21
To maximize a function, minimize the negative of the function
@(x) -f(x)
  1 个评论
Mohammed Bakr
Mohammed Bakr 2020-11-21
编辑:Mohammed Bakr 2020-11-21
how can i do that ..... How can I get maximization (fitness function) curve?

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Fluid Network Interfaces Library 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by