find the equation of tangent to the curve y=2(x^1/2) at (1,2)

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Nishanth G
Nishanth G 2020-11-23
编辑： Stephan 2020-11-23
since i am new to matlab plese help me out with this assignment
find the equation of tangent to the curve y=2(x^1/2) at (1,2)
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Nishanth G
Nishanth G 2020-11-23
syms s(t) f(x)
f(x)=input("enter the function")
m=diff(f,x)
x1=input("enter the value of x for slope point")
y1=input("enter the value of y for slope point")
y=m*(x-x1)+y1
print(y
i got till this i need to apply x1 value in m , how do i do that ?

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Stephan
Stephan 2020-11-23
编辑：Stephan 2020-11-23
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Stephan
Stephan 2020-11-23
编辑：Stephan 2020-11-23
syms f(x)
f(x) = 2*(x^(1/2)) % symbolic function
Df = diff(f,x) % derivative
m = Df([1 2]) % values of slope for x=1 & x=2 in a vectorized manner
m_vals = double(m) % convert symbolic (exact) results to numeric

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