ODE solving lack of span inputs

2 次查看（过去 30 天）
HWIK
HWIK 2020-11-23
编辑： Bjorn Gustavsson 2020-11-23
I have this piece of code and I dont know what is the problem, it says the tspan argument must have at least two arguments.
%Initial conditions
tspan=[0, 168169];
c0=[0.5,0,0];
%Solving for the differential equation for the volume
[t,lnV]=ode45(@cstP_V,tspan,c0);
%Since written in terms of concentration of A, extraxt last value (at time
%t) of the first column
V=exp(lnV(end,1))
%Function is defined
function dlnV=cstP_V(t,C) %Time and initial concentration constants
k=0.0023; %Reaction rate constant
function dC=cstP_C(t,C) %Embeded function determining the rate of change of concentration of compounds
%Assigning inital concentrations
CA=C(1);
CB=C(2);
CC=C(3);
%Defining rate laws
r=k*CA^2;
CA=-r;
CB=r;
CC=r;
%Assigning the rates of change of each compound to the output
dC(1,:)=CA;
dC(2,:)=CB;
dC(3,:)=CC;
end
dCA=cstP_C(t,C); %obtaining rate of change in concentration with initial conditions from main function
[~,C1]=ode45(@cstP_C,[0 1],C); %solving for concentration values (tspan values had to be respecified for after already calling function)
ca=C1(end,1); %determining ca at time t
dlnV=-1*(ca^(-1)*dCA+(k*ca)); %specifying the rate of change in ln(V) from derived relation
end
  2 个评论
Steven Lord
Steven Lord 2020-11-23
Can you show us the mathematical form of the system of ODEs that you're trying to solve? I'm not sure exactly what you're trying to solve based on the code you've posted.
HWIK
HWIK 2020-11-23
Where:
Where at time 0 ca=0 and the tspan from 0 to 168169 s

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Bjorn Gustavsson
Bjorn Gustavsson 2020-11-23
编辑：Bjorn Gustavsson 2020-11-23
OK, you have 2 coupled ODEs. If I expand the D/Dt(log(V(t))) to 1/V(t)*D/Dt(V(t) I'd get something like this:
function dVdtdcadt = odeperhaps(Vca,t)
k = 12; % perhaps some correction...
V = Vca(1);
ca = Vca(2);
dcadt = k*ca^2;
dVdt = -k*ca*V - dcadt*V/ca;
dVdtdcadt = [dVdt;dcadt];
end
These coupled ODEs you then integrate together. You might want to set the ode-options that ensure the solutions are kept positive - check the help and documentation for ode45 and odeset, it should be the 'NonNegative' field that should be used. That ought to make the V and ca in the denominators safe...
Perhaps I misstyped something.
HTH

更多回答（1 个）

Bjorn Gustavsson
Bjorn Gustavsson 2020-11-23
The error is most likely in the second ode45-call. In that subfunction the time t will always be a scalar. You might want to change that to:
[~,C1]=ode45(@cstP_C,[0 t],C);
But that also looks peculiar to me.
HTH
  2 个评论
HWIK
HWIK 2020-11-23
Thank you, I tried that but it was giving me a final walue of infinity, which for the given problem was not a right answer. But then trying different things I ended up getting a more reasonable answer by putting a t time-span of [0 1] for the second call. Although I'm not sure about how that works exactly.
Bjorn Gustavsson
Bjorn Gustavsson 2020-11-23
I'll have to repeat the recommendation of Steven, you might get better help if you show us your ODE-system in mathematical form. The "inner" ODE you use has the fragrance of something "being a bit off" - maybe that equation should be coupled to the others in a more direct way?

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Ordinary Differential Equations 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by