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Subtraction matrix for all values

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Matthew Worker
Matthew Worker 2020-11-25
编辑： N/A 2020-12-4
column 1 - column 2; column 1 - column 3; column 1 - column 4...(rest of subtractions)..olumn 4 - column 4.
How would I approach this?

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回答（1 个）

David Hill
David Hill 2020-11-25
for m=1:size(A,2)
for n=1:size(A,2)
B(:,(m-1)*size(A,2)+n)=A(:,m)-A(:,n);
end
end

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