how to plot a sequence over a given interval
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Hello,
After hours upon hours of trying to work this out and a couple of questions here I am having no luck.
I need to plot a seqeunce over a given interval, I have gotten to the point where the sequence is there however I can't find a way around 'vectors must be the same length'
Here is my code...
n = -20:12
x = repmat([5,4,3,2,1],3 15)
linespace(n)
plot(n,x)
I would expect a saw tooth wave looking graph but I get the above mentioned error.
What am I doing wrong? I don't have enough time to play about with the code to try to figure this out as I need to submit a report tomorrow by 11pmand after trying to figure this out for two or three days I am out of ideas.
Any help will be greatly appriciated.
4 个评论
Image Analyst
2020-11-28
So, n is the x-axis and you want one triangle going from 1 to 5, peaking in the middle, and you want to replicate it 5 more times, for a total of 6 or 198 elements with the final element being n=178?
采纳的回答
Roshan Hingnekar
2020-12-1
In the code mentioned above the length of vector 'n' is 33, the length of vector 'x' is 75, Hence the plot function is giving error.
Use the following code:
n = linspace(-20,12,75);
x = repmat([5,4,3,2,1],3 ,15);
plot(n,x)
xlim([-20 12])
The aboce code should give the saw-tooth output.
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